radius of semi circle = 21cm
area of semi circle = pi*r^2/2
=>22/7*21*21/2
=>11*3*21=693
A-B=357
x+B=693
A+x=1050
A+x=area of triangle
area of triangle = 1/2*base*height
=>1050=1/2*base*height
=>1050/21=base
QR=50
- Devank Karkihalli answered 8 months ago
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Area of semi circle = 1/2 * 22/7 * 21^2 = 693 cm^2
Ar of PQR = 693 + (a-b) = 693 + 357
= 1050cm^2
And Ar of PQR = 1/2.b.h = 1050
therefore, 1/2 * b * 42 = 1050
b = 1050/21
hence base (QR) = 50cm
- Sreyashi Dasgupta answered 8 months ago
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Anirudh Seetharaman’s answer:
https://drive.google.com/file/d/1e9iZlDvK9rp5WqPCiEUDQ-E4y9tWsh–/view?usp=sharing
- Anirudh Seetharaman answered 8 months ago
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Jahaan Kukreja’s answer:
https://drive.google.com/file/d/19N8_z4bs_ngVANAZUcd90DYfl2y8vWhW/view?usp=sharing
- Jahaan Kukreja answered 8 months ago
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