(10^10 – 1)^3=10^30 – 1 – 3*10^10(9999999999)
10^30 will add 1 to the total sum
3*9999999999*10^10=299999999970000000000
299999999970000000000-1=299999999969999999999
total sum of digits = 9*10+9*9+1+2+6=9*20=180
option (c)
- Devank Karkihalli answered 3 months ago
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Jahaan Kukreja’s answer:
https://drive.google.com/file/d/1FAEA0b0qkWlUctwbMxPUyut92XlWpOmr/view?usp=sharing
- Jahaan Kukreja answered 3 months ago
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Anirudh Seetharaman answer’s:
https://drive.google.com/file/d/1cj3hSbByCSAkEyiBt0G08Qr8HP5oqSfz/view?usp=sharing
- Anirudh Seetharaman answered 3 months ago
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