0
0
0
0

(10^10 – 1)^3=10^30 – 1 – 3*10^10(9999999999)

10^30 will add 1 to the total sum

3*9999999999*10^10=299999999970000000000

299999999970000000000-1=299999999969999999999

total sum of digits = 9*10+9*9+1+2+6=9*20=180

option (c)

  • You must to post comments
0
0
Showing 4 results
Your Answer

Please first to submit.