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Solve the above question and post your solution. Also you can log the time you spent on solving the question. This will give you an idea of how much is your problem solving speed.

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perfect cubes under 28 -> 1,8,27

if we take x = 8, then y = 20

since 20 is not a perfect cube, 8 is invalid

1 and 27 satisfy both the equations

if we take x = 27, y = 1

if we take y =27, x = 1

therefore there are 2 pairs of values that satisfy both equations simultaneously

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1^3 = 1

3^3 = 27

therefore

1+3=4

1+27=28

cube root-1=1

cube root-27=3

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