Solve the above question and post your solution. Also you can log the time you spent on solving the question. This will give you an idea of how much is your problem solving speed.
- Tushar Sinha asked 2 weeks ago
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https://docs.google.com/document/d/1-hi0qKL1zmAO_NZGkYwSyoUh2lyrY6jkUgNj6tW9AU4/edit?usp=sharing
Swasti’s answer-
- swasti ranmale answered 2 weeks ago
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perfect cubes under 28 -> 1,8,27
if we take x = 8, then y = 20
since 20 is not a perfect cube, 8 is invalid
1 and 27 satisfy both the equations
if we take x = 27, y = 1
if we take y =27, x = 1
therefore there are 2 pairs of values that satisfy both equations simultaneously
- Devank Karkihalli answered 2 weeks ago
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Anirudh Seetharaman’s answer:
https://drive.google.com/file/d/1bbzLZVsaZhWQSxyPBLe3Z2EmaxvATHnA/view?usp=sharing
- Anirudh Seetharaman answered 2 weeks ago
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Jahaan Kukreja’s answer:
https://drive.google.com/file/d/17eVbVZq3Zl2R6VCV94QCiW2dtiA686jO/view?usp=sharing
- Jahaan Kukreja answered 2 weeks ago
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- prad answered 2 weeks ago
- This was a more rigorous version of the answer
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1^3 = 1
3^3 = 27
therefore
1+3=4
1+27=28
cube root-1=1
cube root-27=3
- Navneet Sai answered 2 weeks ago
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